How can the power be calculated for the SMART control system, considering the use of a 12 volt DC source for the following components, all of which operate on 12 volts DC and
HOW calculat the total current ?
number 4 of KC868-E16V2 ( total 64relay )
number 2 ofof H32B PRO ( total 64relay )
number 2 switch module boards ( total 64 switch )
number 3 contactor 45A 12v dc )
KC868-E16v2 use Omron high quality relay, every relay coin work current about 50mA. so if you have 64 relay, will 64*50mA. Of course, it is necessary to increase the margin, because the peak current will be higher when the relay is opened
KC868-H32B Pro when all 32 relay are ON, current about 800mA
“switch module boards ” i don't know which board you will use, but for these INPUT type of board, current all are very low, will <500mA
contactor use you use 45A 220A, contact need work with 24V dc coin, not use for 12v dc. current about 80mA when turn ON. but peak current will be 1A
attach pic of switch module boards and switch
and I use 29 on/off switches and 6 pir sensor and it needs a 12 volt source as well
for number 4 of KC868-E16V2 ( total 64relay )
64 relay omron = 64*50mA = 3200/1000 = 3.2A
...............
number 2 of H32B PRO ( total 64relay )
when all 32 relay are ON, current about 800mA
= 800*2/1000 = 1.6A
.....................
number 2 of switch module boards
= 2*500/1000 = 1A
total amper = 3.2+1.6+1 = 5.8A
chose power supply above 5.8A
IS the calculation right ?
can send me link of power supply above 5.8A from kincony ? all part i used from kincony